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quadrilateral ABCD is located at A(-2,2) B(-2,4) G(2,4) D(2,2). the quadrilateral is then transformed using the rule (x+2,y-3) to form the image A'B'C'D'. what are the new coordinates of of A'B'C'D'? describe what characteristics you would find if the corresponding vertices were connected with line segments.

User Hkn
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The given rule is a translation to the right (2 steps) and down (3 steps).
In order to find the new coordinates, you need to take the given x and add 2 and the given y and subtract 3.
Therefore:
A' (-2+2 , 2-3) --> (0,-1)
B' (-2+2 , 4-3) --> (0,1)
C' (2+2 , 4-3) --> (4,1)
D' (2+2, 2-3) --> (4,-1)

Since the quadrilaterals ABCD and A'B'C'D' are rectangles, connecting the corresponding vertices would give you a parallelepiped, which means that AA', BB', CC', DD' are parallel and congruent segments.

User Demonguy
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