Let 3x = the length of the first rope
2x = the length of the second rope
This representation is based on the given that the ratio of the two ropes is 3:2.
3x + 2x = sq rt. 250
5x = sq rt. 250
x = sq rt. 250 / 5
x = sq rt. 25(10) / 5
x = 5 sq rt. 10 /5
The five would be cancelled resulting to:
x =sq rt. 10