1 Answer

Ronney · Answer 1 · 2019-01-19T00:05:33+0000

The energy carried by a single photon of frequency f is given by:

E=hf

where
$h=6.6 \cdot 10^(-34) m^2 kg s^(-1)$ is the Planck constant. In our problem, the frequency of the photon is
$f=7.15 \cdot 10^(14)Hz$ , and by using these numbers we can find the energy of the photon:

$E=(6.6\cdot 10^(-34)m^2 kg s^(-1))(7.15 \cdot 10^(14)Hz)=4.7 \cdot 10^(-19)J$

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