Question

What is the area of a parallelogram if its length is x+4 and its height is x+3

Answer 1

Area of a parallelogram is:


`\sf A=bh`

Where 'b' is the base and 'h' is the height. Plug in what we know:


`\sf A=(x+4)(x+3)`

Distribute(multiply everything in the first parenthesis to everything in the second parenthesis):


`\sf x* x=x^2`

`\sf x* 3=3x`

`\sf 4* x=4x`

`\sf 4* 3=12`

So we have:


`\sf A=x^2+3x+4x+12`

Combine like terms(3x + 4x = 7x):


`\sf A=\boxed{\sf x^2+7x+12}`