Let Terry's age be x
Terry = x
Rubin is 5 years older than one third Terry’s age
Rubin = 5 + 1/3x
Sheldon is three years younger than 2 times Rubin’s age.
Sheldon = 2(5 + 1/3x) - 3
If Terry is 6,
Rubin = 5 + 1/3(6) = 5 + 2 = 7
Sheldon = 2( 5 + 1/3 (6)) - 3 = 11
Ans: Rubin is 7 and Sheldon is 11