Question

What is the value of b in the equation (yb) 4= 1/y24

Answer 1

It is -6

Explanation:

Answer 2

The value of b is
`(1)/(y^7)`.

Explanation:

Here the given expression is,

`(yb)^4=(1)/(y^(24))`

`y^4b^4=(1)/(y^(24))` ( Using
`(ab)^m=a^mb^m` on left side )

`y^4b^4y^24 = 1` ( By cross multiplication )

`y^(4+24)b^4=1` ( Using
`a^ma^n=a^(m+n)` on left side )

`y^(28)b^4=1`

`b^4=(1)/(y^(28))`

`b=((1)/(y^(28)))^{(1)/(4)}` (
`a^m=b^n\implies a=b^(n)/(m)` )

`b=\frac{1^{(1)/(4)}}{(y^(28))^(1)/(4)}` (
`((a)/(b))^m=(a^m)/(b^m)` )

`b=\frac{1}{y^{28* (1)/(4)}}` (
`(a^m)^n=a^(m* n)` )

`b=(1)/(y^7)`