Question

KCl(aq) + AgF(aq) → AgCl(s) + KF(aq) If 0.45 moles of potassium chloride are consumed completely and we start with twice as much silver fluoride, how many moles of solid silver chloride will be produced?

Answer 1

0.45 f we use 0.45 moles of KCl completely, we will produce the same amount\of AgCl. The fact about AgF Is irrelevant!

Answer 2

0.45 moles of silver chloride will be produced

Step-by-step explanation

The mole ratios for the reactions are 1 for all reactants and reactants. This means that 1 mol of potassium chloride will react with 1 mol of silver fluoride to produce 1 mol of silver chloride and 1 mol of potassium fluoride.

If only 0.45 mol of potassium chloride is available to react with 0.9 mol of silver fluoride, the potassium chloride will be the limiting reagent in this reaction. This means that only 0.45 mol of each of the product will be formed. This means that only 0.45 mol of silver chloride will be formed.

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