Question

Perform the indicated operation. (2x + y)(3x^2 + y)

Answer 1

`(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)`

Explanation:

The given expression is
`(2x+y)(3x^2+y)`.

We expand the parenthesis using the distributive property to obtain;

`(2x+y)(3x^2+y)=2x(3x^2+y)+y(3x^2+y)`

We expand further to get;

`(2x+y)(3x^2+y)=6x^3+2xy+3x^2y+y^2)`

This gives us;

`(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)`