Perform the indicated operation. (2x + y)(3x^2 + y)

Question

asked Nov 10, 2019 71.5k views

1 Answer

Ajay Sivan · Answer 1 · 2019-11-16T19:48:28+0000

Answer:

(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)

Explanation:

The given expression is
(2x+y)(3x^2+y) .

We expand the parenthesis using the distributive property to obtain;

(2x+y)(3x^2+y)=2x(3x^2+y)+y(3x^2+y)

We expand further to get;

(2x+y)(3x^2+y)=6x^3+2xy+3x^2y+y^2)

This gives us;

(2x+y)(3x^2+y)=6x^3+3x^2y+2xy+y^2)