Question

Where is the vertex of the parabola?

y = x2 + 6x + 7



above the x-axis

on the x-axis

on the y-axis

below the x-axis

Answer 1

below the x axis

Explanation:

i took the test

Answer 2

`\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ \begin{array}{llcccl} y = & 1x^2& +6x& +7\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \left(-\cfrac{ b}{2 a}\quad ,\quad c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{6}{2(1)}~~,~~7-\cfrac{6^2}{4(1)} \right)\implies (-3~~,~~7-9)\implies (-3~~,~~-2)`