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What are the zeros of f(x) = 4x^2 - 12x + 8 (I need a clear explanation on how to solve it)
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What are the zeros of f(x) = 4x^2 - 12x + 8 (I need a clear explanation on how to solve it)

User Senad
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Hello,


4x^2-12x+8=4*(x^2-3x+2)\\ We\ are\ searching\ 2\ numbers\ having\ a\ sum\ of\ 3\ and\ a\ product\ of\ 2.\\ These\ 2\ numbers\ are 1\ and\ 2. 1+2=3\ and\ 1*2=2\\\\ 4x^2-12x+8=0\\ 4*(x^2-3x+2)=0\\ 4*(x-1)(x-2)=0\\ x=1\ or\ x=2\\
User Ashbury
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