Question

This figure consists of a rectangle and semicircle.

What is the perimeter of this figure?
Use 3.14 for pi.


19.42 cm

20.28 cm

23.42 cm

32.84 cm

Answer 1

Try this option:
1. for the semicircle p₁=πr=3.1415*3≈9.4248 cm., where r=3 radius of the semicircle;
for the rectangle p₂=4*2+6=14 cm.
2. totaly: p=p₁+p₂=14+9.4248≈23.4248 cm.

answer: 23.42 cm.

Answer 2

The perimeter of the figure is
`23.42\ cm`

Explanation:

we know that

The perimeter of the figure is equal to the perimeter of the rectangle plus the circumference of a semicircle minus the length of
`6\ cm`

Step 1

Find the perimeter of rectangle

The perimeter of rectangle is equal to

`P=2(L+W)`

In this problem we have

`L=6\ cm`

`W=4\ cm`

substitute

`P=2(6+4)=20\ cm`

Step 2

Find the circumference of a semicircle

The circumference of a semicircle is equal to

`C=\pi r`

we have

`r=6/2=3\ cm` -----> the radius is half the diameter

substitute

`C=3\pi\ cm`

Step 3

Find the perimeter of the figure

`20\ cm+3\pi\ cm-6\ cm=(20+3.14*3-6)=23.42\ cm`