Question

The center of a circle is located at (5, −5) . The radius of the circle is 3.

What is the equation of the circle in general form?


​ x2+y2−10x+10y+41=0 ​

​ x2+y2+10x−10y+47=0 ​

​ x2+y2+10x−10y+41=0 ​

​ x2+y2−10x+10y+47=0 ​

Answer 1

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Explanation:

Answer 2

The equation of a circle is:

`(x - xo) {}^(2) + (y - yo) {}^(2) = r {}^(2)`
(x-5)²+(y+5)²=3²
x²-10x+25+y²+10y+25=9
x²+y²-10x+10y+41=0