Question

Maple syrup has a density of 1.325 g/ml, and 100.00 g of maple syrup contains 67 mg of calcium in the form of ca2+ ions. what is the molarity of calcium in maple syrup?

Answer 1

The molarity of calcium in maple syrup is 33.4 M.

Step-by-step explanation:

To find the molarity of calcium in maple syrup, we need to first convert the given amount of calcium from milligrams to grams. Since there are 1000 milligrams in a gram, 67 mg is equal to 0.067 g. Next, we divide the mass of calcium by the density of maple syrup to find the volume of maple syrup.

Volume of maple syrup = mass of calcium / density of maple syrup = 0.067 g / 1.325 g/ml = 0.0506 ml

Now, we can calculate the molarity of calcium (Ca2+) in maple syrup by dividing the moles of calcium by the volume of maple syrup in liters:

Molarity = moles of calcium / volume of maple syrup = (0.067 g / 40.08 g/mol) / (0.0506 ml / 1000 ml/L) = 33.4 M

Answer 2

density of maple syrup = 1.325 g/ml
1000 ml contains 1325 g of maple syrup
In 100 g of maple syrup - 67 mg of Ca ions
Therefore in 1325 g of maple syrup - 67 mg /100g * 1325 g
= 887.75 mg of Ca
this means in 1000 ml - 887.75 mg of Ca
molar mass of Ca - 40 g/mol
therefore number of moles in 1000 ml - 0.88775 g /40 g/mol
molarity of Ca - 0.022 mol/dm³