Question

Juliana and Maria logged a total of 90 hours working for their dad. Juliana worked 2 hours more than three times as much as Maria. How many hours did Juliana work?

Answer 1

Let

x---------> the hours logged by Juliana

y---------> the hours logged by Maria

we know that

`x+y=90` ---------> equation
`1`

`x=3y+2` ---------> equation
`2`

Substitute equation
`2` in equation
`1`

`(3y+2)+y=90`

`4y+2=90`

`4y=90-2`

`4y=88`

`y=88/4`

`y=22\ hours`

Find the value of x

`x=3y+2`

`x=3*22+2`

`x=68\ hours`

therefore

the answer is

Juliana worked
`68\ hours`

Answer 2

Answer:
Juliana worked 68 hours

Step-by-step explanation:
Assume the hours logged by Juliana is x
Assume the hours logged by Maria is y

We are given that:
1- Total hours logged by both is 90. This means that:
x + y = 90
This equation can be rewritten as:
x = 90 - y ...........> equation I

2- Juliana worked 2 hours more than 3 times as much as Maria. This means that:
x = 3y + 2 ...........> equation II

Substitute with equation I in equation II and solve for y as follows:
x = 3y + 2
90 - y = 3y + 2
88 = 4y
y = 22

Substitute with y in equation I to get x as follows:
x = 90 - y
x = 90 - 22
x = 68

Based on the above:
Hours logged by Juliana = x = 68 hours
Hours logged by Maria = y = 22 hours

Hope this helps :)