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Helpppppppppppppppppppppppppp

Helpppppppppppppppppppppppppp-example-1
User Sabobin
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2 Answers

5 votes
For this case we have that the angle sought is 30 degrees.
Tan30 = - (1/2) / (root (3) / 2)
Tan30 = - (root (3)) / (3)
The tangent is positive in the first quadrant and in the third quadrant.
Therefore the answer is:
Angle 60 in quadrants II and IV
Answer:
Angle 60 in quadrants II and IV
option 3.
User Sconfluentus
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8.3k points
6 votes
Answer:
θ has a 60-degree reference angle and is located in quadrant II or IV

Step-by-step explanation:
First, we will get the reference angle:
√3 / 3 is equivalent to 1/√3
This means that the reference angle for θ is 60
Second, we will locate the quadrant:
Based on the ASTC rule, the tan is positive in the first and third quadrants.
Since the given value is negative, therefore, θ is located in either the second or fourth quadrant

Hope this helps :)
User Odiljon Djamalov
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8.3k points

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