Question

A large bag of marbles contains an equal amount of red, orange, yellow, blue, and green marbles. Brody randomly selects 1 marble from the bag. Which of the following represents the probability of selecting a red, blue, yellow, or green marble

A) 0.8
B) 0.7
C) 0.9
D) 0.6

Answer 1

the answer will be

`(4)/(5) = 0.8`
hope this helps

Answer 2

Answer: The correct option is (A) 0.8.

Step-by-step explanation: Given that a large bag of marbles contains an equal amount of red, orange, yellow, blue, and green marbles. Brody randomly selects 1 marble from the bag.

We are to find the probability of selecting a red, blue, yellow or green marble.

Let n be the number of each color of marbles in the bag.

That is, the number of red, orange, yellow, blue, and green marbles, each equals n.

Let S denote the sample space of selecting a marble from the bag and A denote the event of selecting a red, blue, yellow or green marble.

Then, we have

n(S) = n + n + n + n + n = 5n,

n(A) = n + n + n + n = 4n.

Therefore, the probability of event A is given by

`P(A)=(n(A))/(n(S))=(4n)/(5n)=(4)/(5)=0.8.`

Thus the required probability selecting a red, blue, yellow or green marble is 0.8.

Option (A) is CORRECT.