Answer:
Let's consider this right triangle described in the picture.
∠ABD = ∠CBD, since BD is a bisector.
Angles ∠ADB and ∠BDC are neighbor angles and their sum is equal to 180°.
∠BDC is an exterior angle and ∠BDC=∠ABD+∠ADB.
Similarly, ∠ADB is an exterior angle and ∠ADB=∠CBD+∠BCD
Explanation: