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Factor. 25m^100−121n^16

( 5 m10

−11 n4 ) ( 5 m10 +11 n4 ) (5 m50 −11 n8 ) 2 ( 5 m50 −11 n8 ) ( 5 m50 +11 n8 ) (5 m10 −11 n4 ) 2

1 Answer

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25m¹⁰⁰-121n¹⁶
this question is a difference of squares. the basic equations is when you get 2 square numbers and you have to find their difference ;
x²-y² = (x+ y)(x-y)
you have to then find the product of these factors.
the question given can be rewritten to write the numbers in their square forms
25m¹⁰⁰ - 5²m⁵⁰ˣ² - square root - 5m⁵⁰
121n¹⁶ - 11²n⁸ˣ² - square root - 11n⁸
we have to then factorise them
the answer for 25m¹⁰⁰-121n¹⁶ = (5m⁵⁰ - 11n⁸) (5m⁵⁰ + 11n⁸)
User David Coster
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