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PLEASE HELP NOWWWWWWWW 20 POINTS PLEASE HELP Using the transformation T: (x, y) (x + 2, y + 1). Find the distance named. Find the distance CA (the answer must be in the square r…
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PLEASE HELP NOWWWWWWWW 20 POINTS PLEASE HELP Using the transformation T: (x, y) (x + 2, y + 1). Find the distance named. Find the distance CA (the answer must be in the square r…
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Dec 25, 2019
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PLEASE HELP NOWWWWWWWW 20 POINTS PLEASE HELP
Using the transformation T: (x, y) (x + 2, y + 1). Find the distance named.
Find the distance CA (the answer must be in the square root form)
Mathematics
high-school
George Grigorita
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George Grigorita
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Answer: The length of
AC
is: "
2√2 units
" .
____________________________________________________
Step-by-step explanation:
____________________________________________________
Note
:
(not to scale):
____________________________________________________
C
| \
| \
2
| \ "
c
"
|-- \
| \
|_|______\
A
•
2
(
point
–at which
right angle forms)
_______________________________________________________
Use the "Pythagorean theorem" (since this is a right triangle) to solve for the length of
AC
— which is represented by "
c
" :
a² + b² = c² ;
↔ c² = a² + b² ; Solve for "c" ;
Given: "a = 2 ; b = 2 " ;
→ c² = 2² + 2²
→ c² = 4 + 4 ;
→ c² = 8 ;
Take the "positive square root" of each side of the equation;
to isolate "c" on one side of the equation; & to solve for "c" ;
→ √(c²) = √8 ;
→ c = √8 ;
→ √8 = √4 * √2 =
2√2
.
_____________________________________________________
Answer: The length of
AC
is: "
2√2 units
" .
_____________________________________________________
Keven Wang
answered
Jan 1, 2020
by
Keven Wang
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