Question

A water bed weighs 1025 N, and is 1.5 m wide by 2.5 m long. How much pressure does the water bed exert if the entire lower surface of the bed makes contact with the floor?

a.

3.6 x 10^2 Pa

b.

2.7 x 10^4 Pa


c.

1.2 x 10^3 Pa

d.

2.7 x 10^2 Pa

Answer 1

Answer:
D) 2.7 * 10² Pa

Step-by-step explanation:
To answer this question, we will use the following equation:
pressure =
`(force)/(area)`

1- getting the area:
The water bed is in the form of a rectangle. Therefore, the area can be calculated as follows:
area = length * width
We are given that:
lenth = 2.5 m
width = 1.5 m
This means that:
area = 2.5 * 1.5 = 3.75 m²

2- getting the pressure:
We noted that:
pressure =
`(force)/(area)`

We have the force = 1025 N
We calculated the area = 3.75 m²

Substitute in the above equation to get the pressure as follows:
pressure =
`(1025)/(3.75)`
pressure = 2.7 * 10² Pa

Hope this helps :)

Answer 2

By definition we have to:

`P = F / A`
Where,
F: Force
A: area
For the area we have:

`A = (w) * (l)`
Where,
w: width
l: long
Substituting values we have:

`A = (1.5) * (2.5) A = 3.75 m ^ 2`
Substituting the values we have:

`P = 1025 / 3.75 P = 273.3333333 N / m ^ 2`
Rewriting we have:

`P = 2.7 * 10 ^ 2 Pa`
Answer:
d.
2.7 x 10 ^ 2 Pa