The correct answer is that the reaction is not at equilibrium and will proceed to the right. as Q < Kc
To understand the answer to this question it's mainly a comparison between the Q and Kc value
when we have Kc= [NH3]^2/[N2][H2]^3 = 6.02x10^-2
and the Q value = 3.56x10^-4
SO here by comparing Kc value to Q value, we found that
1) Q < Kc :
in this case, the reaction will move towards the right to increase the products and decrease the reactants, So the reaction is preferring a forward reaction to reach the equilibrium.
2) but when Q> Kc :
the reaction will move towards the left to increase the reactants and decrease the products, So the reaction is preferring a reverse reaction to reach the equilibrium.
3) in case of Q= Kc :
in this case, the reaction is in the equilibrium and don't go right or left shift and the forward and reverse reactions are proceeding at the same rate.
So by comparing our Kc & Q in the question, we found that Q<Kc
∴ the answer is that the reaction is not in equilibrium and will proceed to the right.