Question

What was the hiker's average velocity during part B of the hike? In Part A, a hiker travels four kilometers east from nine to nine-forty-five a.m. In Part B, a hiker travels six kilometers south from nine-forty-five to ten-forty-five a.m. In Part C, a hiker travels four kilometers west from ten-forty-five to eleven-fifteen a.m. In Part D, a hiker travels six kilometers north from eleven-fifteen a.m. to twelve p.m.

Answer 1

You have this in Chemistry. It should be in physics, but never mind that.

A

d = 4 km due east. See note for part B.

t = 45 minutes = 3/4 hour

v = ??

d = v * t

4 = v * (3/4)

v = 4/(3/4) = 4 * 4/3 = 16/3 = 5 1/3

So his rate of travel is 5 1/3 km/hr due east. If you do not give the direction when it says velocity, you are wrong. Velocity has direction.

B

10 45 to 11 45 is 1 hour.

d = v * t

d = 6 km due south (this is actually a displacement which also has direction).

t = 1 hour

6 = v * (1)

6/(1) = v

6/(1) = v

v = 1 km/ hr due south