Answer:
The length of CC' is,
units
Explanation:
Using distance(D) formula for any two points is given by:

As per the statement:
From the graph:
The coordinates of C and C' are:
C = (2, 2) and C' = (7, 4)
Apply the distance formula to find length CC', we have;

⇒

⇒

Simplify:

therefore, the length of CC' is,
units