Question

The point slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y-1- 1-12). What is the standard form of the equation for this line?

Answer 1

The point-slope form of the equation through those points is
.. y -1 = (1/4)(x -12)
Multiply by 4 and subtract the left side to put into general form.
.. x -12 -4(y -1) = 0
.. x -4y -8 = 0
Add 8 to put into standard form
.. x -4y = 8