First, let's consider what information we have.
We are given a right circular cone with a radius of 10 km and a diagonal of 22.4 km.
There are two formulae that we need: one for its volume and one for its surface area.
The volume of a cone is
, where B is the area of the base and h is the height. The base of a cone is a circle, so we use the area of a circle,
, to get
.
We aren’t given the height explicitly; however, using the Pythagorean Theorem, we can find it. Treat the diagonal as the hypotenuse of a right triangle and the radius as a leg. We have
.
Now, we can substitute our values into the formula for volume.

For the surface area, we have the formula
, where l is the diagonal that we had in the beginning.
So, we simply write
.