Question

A positive charge of 6.0 × 10-4 C is in an electric field that exerts a force of 4.5 × 10-4 N on it. What is the strength of the electric field?

Answer 1

The force F produced by an electric field of intensity E on a charge of magnitude q is given by

`F=qE`
In our problem, we know the magnitude of the charge (
`q=6.0 \cdot 10^(-4)C`) and of the force (
`F=4.5 \cdot 10^(-4)N`), so we can find the intensity of the electric field:

`E= (F)/(q)= (4.5 \cdot 10^(-4)N)/(6.0 \cdot 10^(-4)C)=0.75 NC^(-1)`