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For which k will the graph of f(x)=x^2−kx+k^2 cross the x-axis twice?

User Taliana
by
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2 Answers

5 votes

Answer:

K has no solutions.

Explanation:

Because the parabola opens upwards and the y-intercept is non-negative, the parabola cannot cross the x-axis twice. Duh.

User Imike
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2 votes
for the graph to cross the x axis twice, b²-4ac needs to be larger than 0
b=-k, a=1, c=k²
b²-4ac=k²-4k²=-3k²
-3k² will never be larger than 0.
User Roee E
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7.9k points