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What is the minimum value of the parabola y= x^2+5x

User ButuzGOL
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2 Answers

5 votes

Final answer:

The minimum value of the parabola y = x^2 + 5x is -25/4.

Step-by-step explanation:

The minimum value of the parabola y = x^2 + 5x can be found by completing the square.

Rewrite the equation as y = (x^2 + 5x + 25/4) - 25/4, which is equivalent to y = (x + 5/2)^2 - 25/4.

Since the square of a real number is always non-negative, the minimum value of the parabola is -25/4.

User Chloraphil
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8.4k points
3 votes
(-2.5,-6.25)
Hope that helps!
User Lidqy
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