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Find f '(0.3) for f of x equals the integral from 0 to x of the arccosine of t, dt

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By the fundamental theorem of calculus,


\displaystyle(\mathrm d)/(\mathrm dx)\int_0^x\cos^(-1)t\,\mathrm dt=\cos^(-1)x

so that


f'(0.3)=\cos^(-1)0.3\approx1.266

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