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Roman Sterlin · Answer 1 · 2019-04-04T09:47:42+0000

First we solve for y₁
3×5 - 5y₁ = 20
15 - 5y₁ = 20
-5y₁ = 20 - 15
-5y₁ = 5
y₁ = -1
(5, -1)

Now we solve for x₂
3x₂ - 5×2 = 20
3x₂ - 10 = 20
3x₂ = 20 + 10
3x₂ = 30
x₂ = 10
(10, 2)

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