Question

How many moles of caco3 are there in an antacid tablet containing 0.515 g caco3?

Answer 1

`0.00515molCaCO3`

Step-by-step explanation:

Hello,

By following the down below simple mass-mole relationship, the requested moles are computed, considering that the calcium carbonate has a molecular mass of 100g/mol:

`M_(CaCO3)=40+12+16*3=100g/mol\\\\n_(CaCO3)=0.515gCaCO3*(1molCaCO3)/(100gCaCO3)=0.00515molCaCO3`

Best regards.

Answer 2

The moles of CaCO3 which are there in antacid tablet that contain 0.515g CaCO3 is calculated as follows

moles =mass/molar mass

the molar mass of CaCO3 = ( 40 x1)+ (12 x 1) + (16 x 3)= 100 g/mol

moles is therefore= 0.515g/100 g/mol= 5.15 x10^-3 moles