Question

What is the osmotic pressure of a 0.065 molar aqueous NaCl at 298 Kelvin?

Answer 1

3.179 atm

Step-by-step explanation:

Osmotic pressure is expressed as:

π = iMRT , Where

π = osmotic pressure

i = van't Hoff factor

M = molar concentration

R = universal gas constant (0.08206 L·atm/mol·K )

T = absolute temperature in K

In this case, i = 2, M = 0.065, R = 0.08206 and T = 298. Substitute into the formula:

π = 2 x 0.065 x 0.08206 x 298

= 3.179 atm

The osmotic pressure is 3.179 atm.

Answer 2

According to osmotic pressure formula:
π = iCRT
when π is the osmotic pressure
i is van't Hoff factor= 2
R universal gas constant 0.0821
T temperature in Kelvin = 298 K
C is molar concentration of solution =0.065 M
So by substitution, we will get the osmotic pressure:
∴π = 2* 0.065 * 0.0821 * 298 = 3.18 atm