Question

In an electronic circuit, you need a capacitor to store 6.000e-9 J of energy. You have 1.50 volts available to charge it with. What capacitance should you choose?

Answer 1

The electrical energy stored in a capacitor is given by


`E_(cap)= (1)/(2)CV^2`

Since we need E=6.000e-9J, and V=1.5V, we can solve this equation for C:


`2* (6.000*10^(-9) )/(1.5^2V)=C= 5.33*10^(-9)=5.33nF`