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The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT. a.) 0.13 J/g-°C b.) 0.20 J/g-°C c.) 0.78 J/g-°C d.) 0.46
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May 27, 2019
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The amount of heat needed to raise 25 g of a substance by 15°C is 293 J. What is the specific heat of the substance? Use the equation C = q/mΔT.
a.) 0.13 J/g-°C
b.) 0.20 J/g-°C
c.) 0.78 J/g-°C
d.) 0.46 J/g-°C
Chemistry
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Qkyrie
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Answer:
0.78 J/g-°C is the correct answer
Step-by-step explanation:
Tttppp
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May 30, 2019
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Tttppp
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It is so simple and direct substitution in the formula of :
C= Q/ m ΔT
when C is specific heat constant
and Q is heat energy of joul
and m is the mass
and ΔT is the change in temperature
and when we have Q = 293 J & m = 25 g & ΔT = 15 °C so by substitution:
∴C = 293/(25*15)
= 0.78 J/g-°C
∴ 0.78 J/g-°C is the correct answer
Kalbsschnitzel
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Jun 2, 2019
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