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Help please.....!!!!!

Help please.....!!!!!-example-1
User Wilbur
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1 Answer

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The correct answer is: [A]: "Graph A" {the red graph}.
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Note:
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When x = 0 ;

y = f(x) = 5(2)⁻ˣ = 5* (2)⁻⁰ = 5 * 1 = 5 .
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By inspection of the graph, the only given answer choices with graphs that fall on the point "(0, 5)" are:

[A]: "Graph A" (the red graph) ; and:

[B]: "Graph B" (the green graph) .
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Now, let us look at other points and see if the selected points are true values for the given function/ equation;

Start with "Graph B" (the green graph): Upon inspection, it is clear that "(0.5 , 7)" is a point on the graph; that is, for "Graph B" ,
when "x = 0.5" , y = 7" .

Let us plug these values into the equation: y = 5(2)⁻ˣ ; to see if the equation holds true; that is, when "x = 0.5" , does "y = 7" ?

5* 2^(-0.5) = 5 * 0.7071067811865475 ;

→ 5 * (√2/2) =

3.5355339059327375;

→ 3.5355339059327375
\\eq 7 .
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So; we are left with: Choice: [A]: "Graph A" {the red graph}.
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User Mnemosyne
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