Question

A force of 15 N is applied to a spring, causing it to stretch 0.3 m. What is the spring constant for this particular spring?

Answer 1

Hooke's Law for springs is F=kx, where k is the spring constant, F is force and x is the displacement. Here we have


`15N=k0.3m \\ \\ (15N)/(0.3m)=k=50 (N)/(m)`

Note the units are Newtons per meter as we expect. This is the same law regardless if we compress or stretch the spring.

Answer 2

50 N/M I just had this question and this is the answer to it.