Question

PLEASE HELP!!!!! For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work.

y = -2x^2 + 2x +2

Answer 1

vertex = (1/2,5/2) x= 1 + or - square root of 5-2y all over 2

Answer 2

We are given this equation

`y=-2x^(2) +2x+2`

The vertex form is given by:

`y=a(x-h)^(2) +k`

Now let us try to convert our equation into vertex form:

`y=-2x^(2) +2x+2`

Vertex form is given by:

`y=-2(x-0.5)^(2) +2.5`

comparing our equation with vertex form ,

The vertex (h,k) is (0.5, 2.5)

Next we have to find y when x=6, plugging x as 6 in the given equation,

`y=-2(6)^(2) +2(6)+2`

y=-58

So at x=6, y=-58.