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87 g of oxygen gas would occupy how many liters of volume at stp
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87 g of oxygen gas would occupy how many liters of volume at stp

User Fuji Komalan
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1 Answer

2 votes
number of mole : mass/ molar mass

87g/ (2 x 16) = 2.719 mol

volume = number of mole x molar volume
volume = 2.719 x 22.4
volume = 60.906 L
User Kalinin
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