Question

`1,(1)/(8),(1)/(27),(1)/(64),...,(1)/(n^(3)),...`

The denominator of the seventh term is
A.] 125
B.] 216
C.] 343
D.] 513

Answer 1

the answer is C.] 343

Answer 2

Answer: option C) 343

Justification:

The sequence of the denominators is:

term denominator

1 1 = 1^3
2 8 = 2^3
3 27 = 3^3
4 64 = 4^3

5 5^3 = 125
6 6^3 = 216
7 7^3 = 343

And that is the term searched. So, the answer is the option C) 343.