Question

Walt received a package that is 2 1/3 inches long, 6 3/4 inches high, and 8 1/2 inches wide. What is the surface area of the package?

Answer 1

Add whole numbers: 2 + 6 + 8 = 16
Add fractions:

= 1/3 + 3/4 + 1/2

= (8 + 18 + 12) ÷ 24

= 38/24 or 1 14/24 or simplified to 1 7/12

Total surface area = 16 + 1 7/12 or 17 7/12

Answer 2

Answer : The surface area of the package is,
`185.9inch^3`

Step-by-step explanation :

The given package is in cuboid shape. Now we have to calculate the surface area of the package by using volume of cuboid.

Formula used for volume of cuboid is:

`V=2(lb+bh+hl)`

where,

V = volume of package

l = length of package =
`2(1)/(3)inch=(7)/(3)inch`

b = width of package =
`8(1)/(2)inch=(17)/(2)inch`

h = height of package =
`6(3)/(4)inch=(27)/(4)inch`

Now put all the given values in the above formula, we get:

`V=2* [((7)/(3)* (17)/(2))+((17)/(2)* (27)/(4))+((27)/(4)* (7)/(3))]`

`V=2* [(119)/(6)+(459)/(8)+(63)/(4)]`

`V=185.9inch^3`

Therefore, the surface area of the package is,
`185.9inch^3`