Answer:

Explanation:
The problem we are given is

We can write the square root of a fraction as a fraction with a separate radical for the numerator and denominator; this gives us

We can write the whole number 4 as the fraction 4/1; this gives us

We now need to "rationalize the denominator." This means we need to cancel the square root in the denominator. In order to do this, we multiply both numerator and denominator by √(2x); this is because squaring a square root will cancel it:

When multiplying radicals, we can extend the radical over both factors:
