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1 vote
Find the sum of the first thirty consecutive whole numbers.

2 Answers

4 votes

Answer:

435

Explanation:

The gouse method or something.

(29*30)/2=435

User Theron Luhn
by
8.3k points
6 votes

The sum of the first thirty consecutive whole numbers can be represented by the following series


0+1+2+3+4+....+29\\ \\Sum \; of\; first \; 30\; whole \; numbers\; =\; Sum\; of\; first \; 29\; Natural\; Numbers\\ \\1+2+3+4+...+29 \\ \\ Formula\\ 1+2+3+....+n=(n(n+1))/(2) \\ \\ Substituting\; 29\; for\; n,\; we\; get...\\ \\ 1+2+3+4+...+29=(29(30))/(2)=29 * 15=435

Conclusion:

The sum of the first thirty consecutive whole numbers is 435.

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