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If f(x)=4^x-1+6 and g(x)=2x-5, what is (f-g)(x)? A. (f-g)(x)=4^x-1-2x-1 B. (f-g)(x)=4^x-1-2x+11 C. (f-g)(x)=4^x-1-2x-11 D. (f-g)(x)=4^x-1-2x+1
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If f(x)=4^x-1+6 and g(x)=2x-5, what is (f-g)(x)?

A. (f-g)(x)=4^x-1-2x-1
B. (f-g)(x)=4^x-1-2x+11
C. (f-g)(x)=4^x-1-2x-11
D. (f-g)(x)=4^x-1-2x+1

User Ahmad Habib
by
8.2k points

2 Answers

3 votes

Answer:

B is correct.

Explanation:

User Ugurcan Yildirim
by
7.8k points
1 vote
I believe the answer is
B. (f-g)(x)=4^x-1-2x+11
(f-g)(x) = (4^x-1+6) - (2x-5)
apply like terms while retaining order of operations
6 - (-5) = 11
4^x - 1 - 2x + 11
I'm fairly certain, I just did this section, but just in case, sorry!
User Damien B
by
8.4k points
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