Question

Which comparison is correct for the values of f(x) and g(x) when x=−1 ?

Function A: f(x)= −x^2+1

Function B:



f(−1)>g(−1)

f(−1)=g(−1)

f(−1)

Answer 1

`f(-1)>g(-1)`

Explanation:

we are given

`f(x)=-x^2+1`

We can plug x=-1 and find f(x)

we get

`f(-1)=-(-1)^2+1`

`f(-1)=-1+1`

`f(-1)=0`

now, we can find g(-1)

we can look at the table and find g(-1)

so, we get

`g(-1)=-4`

we know that

-4 is less than 0

so,

`g(-1)<f(-1)`

or we get

`f(-1)>g(-1)`