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Factor the trinomial x^2 - 8x + 16

1 Answer

5 votes
Hey there mate!

Your answer:
\boxed{(x-4)^2}


Factoring : x^2-8x+16 \\ \\ \\ \left[\begin{array}{ccc} -16 + -1 = -17 \\ \\ -8 + -2 = -10 \\ \\ -4 + -4 = -8\end{array}\right] (That's \ it!) \\ \\ \\ Add \ up \ the \first \ 2 \ terms, \ pulling \ out \ like \ factors : \\ \\ x * (x-4) \\ \\ Add \ up \ the \ last \ 2 \ terms, \ pulling \ out \ common \ factors : \\ \\ 4 * (x-4) \\ \\ Multiply \\ \\ \boxed{(x-4) by (x-4) } \\ \\ \\


Your \ correct \ correct \ answer \ would \ be... \\ \boxed{\boxed{(x-4)^2}}

I hope this helps you!
User Wandarkaf
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