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2 votes
what is the solution to the following system?

5x+2y+z=4
x+2z=4
2x+y-z=-1


A. x = 0, y = 1, z = 2

B. x = 1, y = –1, z = 2

C. x = 1, y = 0, z = –1

D. x = 2, y = 1, z = 0

User Erikbozic
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2 Answers

6 votes
→→→A. x = 0, y = 1, z = 2
6 votes
We solve the system by applying the following steps:
1) Write two of the variables in terms of the third variable. For this case we write x, y in terms of z.
2) Substitute the expressions in the first equation since it relates all the variables.
3) Clear z.
4) with the value of z, find x, y
Answer:
A. x = 0, y = 1, z = 2
See attached image.
what is the solution to the following system? 5x+2y+z=4 x+2z=4 2x+y-z=-1 A. x = 0, y-example-1
what is the solution to the following system? 5x+2y+z=4 x+2z=4 2x+y-z=-1 A. x = 0, y-example-2
User NavaRajan
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7.1k points