Question

A substance has a specific heat of 0.870 J/g°C. It requires 2,000.0 joules to increase the temperature of 10.0 grams of the substance from its original temperature to its final temperature.

By how many degrees did the substance increase?
87.0°C
174°C
230°C
1,740°C

Answer 1

Answer:Answer is C. 230 degrees celsius.

Explanation:Edge 2023

Answer 2

Answer:
`230^0C`

Step-by-step explanation:

`Q=m* c* \Delta T`

q = heat absorbed or released by a substance = 2000.0 J

m= Mass of substance = 10.0 g

c = specific heat of the substance =
`0.870 J/g^0C`

`\Delta T=T_f-T_i` = Change in temperature

Putting in the values we get:

`2000.0J=10.0g* 0.870J/g^0C* \Delta T`

`\Delta T=230^0C`

Thus the temperature changed by
`230^0C`.