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Question 5 (1 point)
What is the molarity of a solution when 80.0 g of sodium chloride (NaCl) are dissolved in 500.0 mL of water?
2.74 M
1.45 M
1.37 M
5.25
Questions

Answer 1

2.74 M

Step-by-step explanation:

Given data:

Mass of sodium chloride = 80.0 g

Volume of water = 500.0 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the mL into L.

500.0 mL× 1 L /1000 mL = 0.5 L

In next step we will calculate the number of moles of sodium chloride.

Number of moles = mass/molar mass

Number of moles = 80.0 g/ 58.4 g/mol

Number of moles = 1.37 mol

Molarity:

M = 1.37 mol/ 0.5 L

M = 2.74 M