Question

If a propane heater burns 38.95 g C3H8, it consumes 38.95 mol C3H8. 0.8830 mol C3H8. 1 mol C3H8. 44.10 mol C3H8.

Answer 1

Option-2 (0.8830 mol C₃H₈) is the correct answer.

Solution:

In statement we are given with the amount of propane gas and are asked to find out the moles for given mass.

As we know mass is related to moles as follow,

Moles = Mass / M.mass ----- (1)

Data Given:

Moles = ??

Mass = 38.95 g

M.mass = (C)3 + (H)8 = (12)3 + (1)8 = 36 + 8 = 44 g/mol

Putting values in equation 1,

Moles = 38.95 g / 44 g/mol

Moles = 0.8854 Moles

Answer 2

The answer is 0.8830 mol C3H8.

Here's how the answer was generated:

We do know that all the choices are in moles, in that case, we divide the 38.95 g of propane (C3H8) by the molar mass which is:

C = 12.01
H = 1.01

C3H8 = 3 * 12.01 + 8 * 1.01 = 44.11
Divide 38.95 g by 44.11 g/mol and the answer will be 0.8830 mol C3H8.