Question

IF SOMEONE COULD HELP ME WITH THIS THAT WOULD BE GREAT

Answer 1

prove
m∠5+m∠2+m∠6=180°

we have that
m∠1+m∠2+m∠3=180° equation I

m∠1=m∠5 -------- > internal alternate angles equation 2

and

m∠6=m∠3-------- > internal alternate angles equation 3

I substitute equation 2 and equation 3 in equation I

m∠1+m∠2+m∠3=180°-------- > m∠5+m∠2+m∠6=180°------- > is ok